Help with use of regular expression
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Problem: I have a cell array of strings
TrajLocationCompact(1, 3).locationIdCompact1
ans =
'1 1 1 1 1 32'
'29 7 1 1 2 2 2 1 1 29'
'2 1 1 2 1 1 1 1 1 1 1'
'29 29 29 39 39 29'
'29 29 37 29 29 29 29'
'29 3 2 2 1 2 1 1 1 1 1 2'
'29 3 1 1 2 1 1 2 1 2 1 29'
'3 1 1 2 1 1 2 1 1 1'
'29 29 29 29 29 29 29 29 29 1 2 2 16 5 1 1 2 1'
'29 29'
'29'
I want to trasform it in this way
'1 1 1 1 1 32' --> 1 32
'29 7 1 1 2 2 2 1 1 29' --> 29 7 1 2 1 29
'2 1 1 2 1 1 1 1 1 1 1' --> 2 1 2 1
'29 29 29 39 39 29' --> 29 39 29
'29 29 37 29 29 29 29' --> 29 37 29
'29 3 2 2 1 2 1 1 1 1 1 2' --> 29 3 2 1 2 1 2
'29 3 1 1 2 1 1 2 1 2 1 29' --> 29 3 1 2 1 2 1 29
'3 1 1 2 1 1 2 1 1 1' --> 3 1 2 1 2 1
'29 29 29 29 29 29 29 29 29 1 2 2 16 5 1 1 2 1' --> 29 1 2 16 5 1 2 1
'29 29' --> 29
'29' --> 29
Can you help me to find a regular expression that do it?
0 Comments
Accepted Answer
Stephen23
on 11 Dec 2015
Edited: Stephen23
on 11 Dec 2015
Your example indicate that you want to convert these string numbers to numeric, and then collect the runs of one value together into one element. This is easy using diff:
>> C = {'1 1 1 1 1 32','29 7 1 1 2 2 2 1 1 29'};
>> D = cellfun(@(s)sscanf(s,'%f'),C,'UniformOutput',false);
>> E = cellfun(@(v)v([true;diff(v)~=0]),D,'UniformOutput',false);
>> E{:}
ans =
1
32
ans =
29
7
1
2
1
29
2 Comments
Joseph Cheng
on 11 Dec 2015
to expand on Stephen's you can write a function as such
function cellout = mycellfun(cellin)
numbers = str2num(cellin);
points = [1 find(diff(numbers)~=0)+1];
cellout = num2str(numbers(points));
end
and use it on your data
test = cellfun(@mycellfun,temp,'uniformoutput',false)
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