Trying to create a vector in steps of 0.5
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I'm trying to get the vector to go up in steps of 0.5.
v_numerical(0.5)= g.*0.5;
for i = 1:0.5:10
v_numerical(i) = v_numerical(i-0.5)+(g-((c.*v_numerical(i-0.5))./m).*(0.5));
end
However whenever i try running it I get the error:
Attempted to access v_numerical(0.5); index must be a positive integer or logical.
Any idea how I can solve this problem? Many thanks in advance!
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Accepted Answer
Stephen23
on 24 Jan 2016
Edited: Stephen23
on 24 Jan 2016
MATLAB indices start at one, and must be whole numbers (i.e. no fraction allowed). With your code you are trying to index with 0.5 and lots of other fractions, which will always be an error, like this:
>> A(0.5) = 3 % fraction index is an error
??? Attempted to access (0.5); index must be a positive integer or logical.
>> A(1) = 3 % whole number index is okay
A =
3
You can easily create a vector with 0.5 spacing:
V = 1:0.5:10;
but when I tried to fix your code it made very little sense to me what you are trying to achieve. Can you please explain what you are trying to do with this code: what should the input and output be?
More Answers (1)
Nemanja
on 9 Jun 2023
Edited: Nemanja
on 9 Jun 2023
g = linspace(1:10:20) %goes from 1 to 10 and has 20 elements because 10/20 is 0.5 so it will go up from 1 to 10 with 0.5 spacing%
1 Comment
Stephen23
on 9 Jun 2023
"goes from 1 to 10 and has 20 elements because 10/20 is 0.5 so it will go up from 1 to 10 with 0.5 spacing"
No, you are making this error:
It is easy to check that your statement is incorrect: did you try running the code yourself before posting here?
g = linspace(1,10,20) % fixed incorrect syntax
Tip: to split the range 1..10 into steps of 0.5 then you need 19 elements. Lets try it now:
g = linspace(1,10,19)
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