functionalDerivative, deriving as function of derivative?

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Hello all,
I'm attempting to compute a Lagrangian EQs of motion.
Part of this requires computing the partial derivative of L with respect to variable_dot, the derivative of the variable.
syms t m1 m2 x1(t) x2(t) k
K = (1/2)*m1*diff(x1,t)^2;
P = (sym(1)/2)*k*(x1-x2)^2;
L = K - P
diff( functionalDerivative( L, diff(x1)) ,t) - functionalDerivative(L,x1)
functionalDerivative() does not like the form of the "diff(x1)". Is there a way to do this?
Thanks a lot, Dan

Answers (1)

John BG
John BG on 8 Feb 2016
Takeshita san has a detailed explanation how to solve the Euler-Lagrange equation with MuPAD:
If you find this link useful, please click on the thumbs-up vote link above,
thanks in advance
John
  1 Comment
Dan D
Dan D on 8 Feb 2016
I was hoping that the new functionalDerivative() function would make this a little cleaner. it works great for the partial derivative in respect to x(t), it just doesn't seem to be able to handle diff(x(t)) as a parameter.

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