The number of columns in A must be the same as the number of elements of f. i couldnt get this ,how can i solve it

>> f=[65 73 63 57;67 70 65 58;68 72 69 55;67 75 70 59;71 69 75 57;69 71 66 59];
>> A=[1 1 1 1;1 1 1 1;1 1 1 1;1 1 1 1;1 1 1 1;1 1 1 1];
>> b=[1;1;1;1;1;1];
>> Aeq=[1 1 1 1 1 1 ;1 1 1 1 1 1 ;1 1 1 1 1 1 ;1 1 1 1 1 1];
>> beq=[1;1;1;1];
>> lb=[0;0;0;0;0;0];
>> ub=[1;1;1;1;1;1];
>> intcon=[1,2,3,4,5,6];
>> intlinprog(f,intcon,A,b,Aeq,beq,lb,ub)
Error using intlinprog (line 122)
The number of columns in A must be the same as the number of elements of f.

Answer 1

[Walter Roberson]

"f can also be an array. Internally, intlinprog converts an array f to the vector f(:)"

So your 6 x 4 array for f, is treated as a 24 x 1 vector for f.

You A is also 6 x 4, but "A has size M-by-N, where M is the number of constraints and N = numel(f)". So your A would need to be something-by-24. You have 6 elements in b, so you have 6 constraints, so your A would have to be 6 x 24.

Likewise when Aeq is not empty, it has to be Meq x N where N is numel(f) and Meq is the number of equality constraints. Your beq is length 4 so you have 4 equality constraints, so your Aeq would need to be 4 x 24.