Asked by Lisa Justin
on 6 Feb 2012

i have a 42*16384. how do i average it so that i get a new matrix of size 42*2048 (if N=2048 represents one revolution and N=16384 represents 8 revolutions).

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Answer by Andrei Bobrov
on 6 Feb 2012

Accepted answer

`data` - your array [42x16384]

**EDIT**

out = mean(reshape(data,size(data,1),[],8),3);

**eg:**

`data` - your array [55x72000]

out = mean(reshape(data,size(data,1),[],3),3);

**or**

out = squeeze(mean(reshape(data,size(data,1),3,[]),2)) ;

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Lisa Justin
on 6 Feb 2012

??? Error using ==> reshape

Product of known dimensions, 216000, not divisible into total number of elements,

3960000.

Lisa Justin
on 6 Feb 2012

out = squeeze(mean(reshape(data.',size(data,2),8,[]),2)).'

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