How to find different values of a function for i = 0 to 10

i want to calculate different values of h_k for k = 0 to 10 and alpha = beta = 1/2 where

how to solve this in MATLAB?

Answer 1

[KSSV]

It is a Home Work problem. As gamma function is involved, I am helping you out.

clc; clear all 
a = 1/2 ;
b = 1/2 ;
hk = zeros(10,1) ;
for k = 1:10
    hk(k) = 2^(a+b+1)*gamma(k+a+1)*gamma(k+b+1)/((2*k+a+b+1)*gamma(k+1)*gamma(k+a+b+1));
end

[R shah]

Thanks a lot for your prompt reply but still the results are not appearing. how could i display the results?

[Walter Roberson]

disp(hk)

[R shah]

hey i've made this change and getting the desired results, kindly check;

clc; clear all 
a = 1/2 ;
b = 1/2 ;

for k = 0:4
    hk = 2^(a+b+1)*gamma(k+a+1)*gamma(k+b+1)/((2*k+a+b+1)*gamma(k+1)*gamma(k+a+b+1));
    display(hk)
end

[Walter Roberson]

If you want to be able to compute with them later instead of just displaying them, then assign into an array like was shown,

a = 1/2 ;
b = 1/2 ;

for k = 0:4
    hk(k+1) = 2^(a+b+1)*gamma(k+a+1)*gamma(k+b+1)/((2*k+a+b+1)*gamma(k+1)*gamma(k+a+b+1));
    display(hk(k+1))
end

The k+1 instead of k by itself is to allow you to start from 0, as MATLAB does not allow you to index at location 0.

Answer 2

[Andrei Bobrov]

a = 1/2 ;
b = 1/2 ;
k = 1:10;
hk = 2^(a+b+1)*gamma(k+a+1).*gamma(k+b+1)./((2*k+a+b+1).*gamma(k+1).*gamma(k+a+b+1));

[R shah]

u've given a good clue but i've added a for loop in this code which is;

clc; clear all 
a = 1/2 ;
b = 1/2 ;

for k = 0:10
    hk = 2^(a+b+1)*gamma(k+a+1)*gamma(k+b+1)/((2*k+a+b+1)*gamma(k+1)*gamma(k+a+b+1));
    display(hk)
end

thanks a lot for your help