calculating and plotting non continuous function

Asked by Bart on 2 Mar 2012
Latest activity Answered by Walter Roberson on 2 Mar 2012

Hi,

I'm trying to calculate and plot the surface area of what I think is a 3d surface function. The problem that I have is that the function is the sum of "chucks" of a function. Here's the code:

```>> t2 = ((a1*(trest - b1)^c1)+d1)*i^(i*((a2*trest^b2) + c2)) +     ((a3*(trest-b3)^c3)+d3);
>> ton = 0:.1:60;
>> trest = 0:.1:60;
>> [X,Y] = meshgrid(ton,trest);
>> Ttot = 120;
>> syms x, t;
>> total = 0;
>> for i = 1:(Ttot/(ton+trest))
total = total + double(int(a*exp(b*t) + c*exp(d*t),t,t2,ton+t2));
end
surf(total,X,Y)
??? Error using ==> mrdivide
Matrix dimensions must agree.
```

Any ideas how I can get around this problem? The variables on which the for loop is dependent also determine the value of the surface area. The problem is that I'm counting up to a variable, and I don't really see a way around it. Was hoping Matlab would :) Any help is greatly appreciated!

Products

No products are associated with this question.

Answer by Walter Roberson on 2 Mar 2012

Try

```Ttot ./ (ton+trest)
```

Answer by Jonathan Sullivan on 2 Mar 2012

Brat. Your code is illegible. Please use the "code" button when typing it so that it's easier to follow.

Bart on 2 Mar 2012

trying to asap :)

Bart on 2 Mar 2012

done!

Answer by Bart on 2 Mar 2012

anybody? :D