hi, i want to remove an item from array, but get error
this is my code
for i=1:12 if align(1,i)=='-' & align(2,i)=='-' align(1,i)=; align(2,i)=; end end
??? A null assignment can have only one non-colon index.
Error in ==> testt at 6 align(1,i)=;
thanks in advance
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When you remove a character, the string is getting shorter. But the FOR-loop tries to access all characters of the initial size.
Either run the loop in reverse direction:
align(1,:) = ['asd-as---tyr'; ... 'fg--ds--h-ty'];
for i=12:-1:1 if align(1,i)=='-' & align(2,i)=='-' align(:,i) = ; end end
Or use a vectorized approach, which is faster and nicer:
align(align(1, :)=='-' & align(2, :)=='-', :) = ; % No FOR loop, no IF
[EDITED]: Typo in the line above (thanks Walter!):
align(:, align(1, :)=='-' & align(2, :)=='-') = ;
To remove the minus sign you could use:
align= char(strrep(align(1,:),'-','') ,strrep(align(2,:),'-','') )
I can see how you would find that error message a bit cryptic, but here is what is going on.
Your variable align is a 2x12 character array. With your line of code
is going to attempt to remove the upper-left corner of that array. But MATLAB can't do that. There cannot be a character array that has one row of 11 elements, and a second row that is 12 elements. One element cannot be "empty" in that way. (That is what error message is saying.) You can only do the null assignment for a whole row or column at once.
So, in your case, you could combine your two null assignment statements into the single statement
align(:,i) = ;
and MATLAB will delete the i'th column, in its entirety.
Be aware that your array align is going to keep getting trimmed, as it goes through the for loop, so it will no longer be width 12.