CALCULATION OF MAXIMUM VALUE IN EVERY ROW

2 views (last 30 days)
suppose there is a matrix of 3x3 size i want to calculate the maximum value in every row.
ex: 3 4 5
6 9 0
1 2 3
the result i should get at the end should be like this
0 0 1
0 1 0
0 0 1
[EDITED, code formatted, Jan]
  2 Comments
Brahima DRABO
Brahima DRABO on 16 Jan 2016
suppose your matrix is A: result = A==max(A,[],2)
Stephen23
Stephen23 on 16 Jan 2016
@Brahima DRABO: you should put this as an answer too: you would get votes.
Note to others: ignore the accepted answer, it is very poor code.

Sign in to comment.

Accepted Answer

Bart
Bart on 6 Mar 2012
try this:
suppose the input matrix is A, the output result matrix is B;
max = 0;
k = 0;
l = 0;
for i=1:3
for j=1:5
place(i,j) = 0;
end
end
for i=1:3
for j=1:3
if A(i,j)>=max
max = A(i,j);
place(i,j) = 1
end
end
end
for k=1:3
for l=1:3
if place(k,l) = 1
if place(k,l+1) = 1
B(k,l) = 0;
end
if place[k,l+2) = 1
B(k,l) = 0;
else B(k,l) = 1;
end
else B(k,l) = 0;
end
end
end
  1 Comment
Jan
Jan on 7 Mar 2012
Shadowing the built-in function "max" by a variable is a frequent source of porblems and bugs.
The creation of the variable "place" element by element is very inefficient and should be avoided. "place = zeros(3, 5);" is nicer, faster and consumes less memory. Although this is a tiny example here and runtime does not matter, it is a good idea to follow a clean programming style.
Using nested loops to create B element by element is slow also, again due to the missing pre-allocation.
It is not useful to declare k=0 and l=0 at the beginning.
The algorithm wastes a lot of time. Try it with a 1000x1000 array to feel the difference.

Sign in to comment.

More Answers (3)

Jonathan Sullivan
Jonathan Sullivan on 7 Mar 2012
m = [ 3 4 5
6 9 0
1 2 3];
mx = max(m,[],2); % EDIT: was max(m,2); Oops
out = bsxfun(@eq,m,mx);

Jan
Jan on 6 Mar 2012
[v, sub] = max(a, [], 2); % [EDITED], was "max(a, 2)"
sa = size(a);
b = zeros(sa);
index = sub2ind(sa, 1:sa(1), sub);
b(index) = 1;
I cannot try it currently and I find the documentation of sub2ind confusing in this point: Perhaps the 2nd and 3rd argument must be swapped: sub2ind(sa, sub, 1:sa(1)).
  2 Comments
raj
raj on 7 Mar 2012
there is an error in your code... in the 1st line

Sign in to comment.


raj
raj on 7 Mar 2012
even the imregionalmax function works well

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!