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Asked by Joe on 16 Mar 2011

I am writing a program to generate a neural network using NEWFF.

I have 5 input variables (A through E) which are currently being input as an array:

input = [ A1 A2 A3 A4 A5 B1 B2 B3 B4 B5 C1 C2 C3 C4 C5 D1 D2 D3 D4 D5 E1 E2 E3 E4 E5 ];

There is 1 target vector:

target = [ T1 T2 T3 T4 T5 ];

I input this to NEWFF as:

net = newff( input, target );

I would think this would generate a network with 5 inputs and 1 output. However, no matter how I format the input variables the network is defined as having only 1 input.

Can anyone clarify what the issue is?

Thanks, Joe

P.S. I am using R2009B

*No products are associated with this question.*

Answer by Catherine DA GRACA on 10 Apr 2011

Your input array only has one row in it - MATLAB ignores the line breaks. Use semi-colons to separate the values:

input = [ A1 A2 A3 A4 A5; B1 B2 B3 B4 B5; C1 C2 C3 C4 C5; D1 D2 D3 D4 D5; E1 E2 E3 E4 E5 ];

Walter Roberson on 10 Apr 2011

Not correct, Catherine.

>> [1 2 3 4 5

6 7 8 9 10

11 12 13 14 15]

ans =

1 2 3 4 5

6 7 8 9 10

11 12 13 14 15

When a line break is hint in an array and there is no continuation marker, it is treated as a vertical concatenation.

Joe on 11 Apr 2011

Catherine, the intent was not to convey the exact way I'd written the code, it was more to convey the fact that it I would have thought a 5 by 5 matrix would result in a system of 5 inputs, each consisting of elements, where it appears that that is not the case. In fact, the way the matrix is built in the code is much more complex.

Answer by Walter Roberson on 10 Apr 2011

Please recheck the documentation:

- T SN x Q2 matrix of Q2 sample SN-element target vectors

Your target is 1 x 5 so SN is 1, so you are defining a network with a single input.

Joe on 12 Apr 2011

Thank you for your response Walter, but could you please elaborate? The way I read that line of the documentation is that The number of rows (SN) determines the number of elements in each output, while the number of columns (Q2) determines the number of samples per output... This does not impact the number of inputs fed to the network, and a quick test of the function bears this out (a dummy set of matrices run through newff, one with a T matrix which is 1x3 and the other which is 3x1, both result in a network with only 1 input)

Considering the variable P from the documentation, which is where I would expect the number of inputs to be determined:

P: R x Q1 matrix of Q1 sample R-element input vectors

R is the number of elements in each input and Q1 is number of samples... and no matter what the structure of this matrix is it doesn't seem to impact the "number of inputs".

I think I'm missing something fundamental here.

Answer by Kukuh on 25 Apr 2012

yes joe...I have same problem with you,,,my NN can't running when I use multi input like that. please help me.. thanks

Answer by Greg Heath on 25 Apr 2012

[I N ] = size(p)

[O N ] =size(t)

net = newff(p,t,H);

Results in a FFMLP with I-H-O node topology.

Hope this helps.

Greg

Greg Heath on 25 Apr 2012

I think what the documentation fails to make clear:

Regardless of the size of I and O, when you type the command

net

it will show only 1 (vector-valued/I-dimensional) input and 1 (vector-valued/O-dimensional) output.

Hope this helps

AND

Hope the documentation re this is modified in all of the many places

that it is (ab)used.

Greg

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