Hello there, I have a short question, as for some reason a for loop doesn't function.
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RT is a matrix and krit_out1 is a vector. There is no error message, but the loop is stuck in the first row of the matrix and I don't find the reason.. Can someone help me?
for i = 1:50
RT(RT(:,i)> krit_out1(i)) = NaN;
end
1 Comment
Stephen23
on 24 Oct 2017
Loops are not required to solve this. See Jan Simon's answer for a simple and efficient solution.
Accepted Answer
Birdman
on 23 Oct 2017
RT=ones(50,50);krit_out1=zeros(50,1);
for i=1:50
for j=1:50
if(RT(j,i)>krit_out1(j))
RT(j,i)=NaN;
end
end
end
Try this.
2 Comments
Jan
on 23 Oct 2017
krit_out1( i ) instead of j.
The vectorization of such loops is not only nice and processed efficiently, but without indices, there are less chances for typos.
More Answers (2)
Ray
on 23 Oct 2017
Try the following. It looks like you intend to operate on the ith column using the ith element of a vector called krit_out1:
for i = 1:50
RT(RT(:,i)> krit_out1(i) ,i) = NaN;
end
4 Comments
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