Newton Raphson question code and answer plz urgent

f1(x1, x2) = 10x1sinx2 + 2 = 0
f2(x1, x2) = 10x1^2 − 10x1cosx2 + 1 = 0

need to find x1 and x2 5 iterations

at 0 x1 and x2 = 1 and 0 respectively

i've looked for some codes...but just hard to understand..wish they asked me to do it by hand lol...not very good with matlab.

Need to know by tomorrow afternoon latest :(

Thanks to anyone that helps!

[James Tursa]

Please post your code so we can comment on it.

[Walter Roberson]

http://www.mathworks.com/matlabcentral/answers/29922-why-your-question-is-not-urgent-or-an-emergency

[Carlos Mallqui]

sorry about the urgent..don't have to take it that way either..in a sense it is urgent...but not obligating anyone to respond to me...only if they have time to help would be awesome....if not well..thats fine too i understand people have many things to do.

below i added somethings..

[Walter Roberson]

That makes it "time sensitive" rather than "urgent".

Answer 1

[Carlos Mallqui]

sorry about the urgent..don't have to take it that way either..in a sense it is urgent...but not obligating anyone to respond to me...only if they have time to help would be awesome....if not well..thats fine too i understand people have many things to do.

clear, clc
x = [1;1];
nit=10;
for i=1:nit
f(:,i) = [x(1)*x(1)-x(2)-1; x(2)*x(2)-x(1)-1];
delta = 4*x(1)*x(2)-1;
Jinv = (1/delta)*[ 2*x(2) 1; 1 2*x(1)];
dx(:,i) = -Jinv*f(:,i);
x(:,i+1) = x(:,i) + dx(:,i);
end
numofit = (0:nit)’;
output = [numofit x’];
fprintf(’\n nofit \t x(1) \t x(2) \n’);
fprintf(’-------------------------------\n’);
fprintf(’%7.0f \t %7.4f \t %7.4f\n’,output’);

that is the equation posted as a guide...to solve this other problem

f1(x1, x2) = x1^2− x2 − 1 = 0
f2(x1, x2) = x2^2− x1 − 1 = 0

where initial conditions are [1, 1]

I just wanted to know how would i apply it in my case with the other equations...im really not good with the commands..

if anyone can help me out I will appreciate it :)

thnaks

[Carlos Mallqui]

clear, clc

x = [1;1];

nit=10;

for i=1:nit

f(:,i) = [x(1)*x(1)-x(2)-1; x(2)*x(2)-x(1)-1];

delta = 4*x(1)*x(2)-1;

Jinv = (1/delta)*[ 2*x(2) 1; 1 2*x(1)];

dx(:,i) = -Jinv*f(:,i);

x(:,i+1) = x(:,i) + dx(:,i);

end

numofit = (0:nit)’;

output = [numofit x’];

fprintf(’\n nofit \t x(1) \t x(2) \n’);

fprintf(’-------------------------------\n’);

fprintf(’%7.0f \t %7.4f \t %7.4f\n’,output’);

code was pasted unproperly

[Geoff]

then please edit your answer, highlight the code and press the 'code' button.

[Carlos Mallqui]

done already fixed it thanks....now it can be seen properly..but still this code is not for the actual problem i wanna solve..but it was the example used