finding the minimum value

Asked by kash on 10 May 2012
Latest activity Commented on by Sargondjani on 11 May 2012

I have a code performing inverse dualtree dwt

for j1 = 1:size(A1_20,3)
    for j = 1:J
    % loop thru subbands
    for s1 = 1:2
        for s2 = 1:3
            w{j}{s1}{s2} =A1_20(:,:,j1);
            y1 = idualtree2D(w, J, Fsf, sf);
            Er= mean2((single(x) - single(y1)).^2);
            final_col2{j1}=Er;
end
end
end
end

I have 5 images w denotes it,and A1_20(:,:,j1) contains 20 matrices of ,I have multiplied those matrices,with image so for each image i get 20 images and have found error,now i want to display the image with minimum error ,like this i want to do for 5 images

please help

0 Comments

kash

Products

No products are associated with this question.

2 Answers

Answer by Sean de Wolski on 10 May 2012

Use the second output argument from min() and the correct dim input to min() to tell you where the minimum is.

1 Comment

kash on 10 May 2012

Sean i cant understand ,please can you explain it please ,if possible with an example

Sean de Wolski
Answer by Sargondjani on 10 May 2012

i have difficulty understanding your code... but lets say you have: w(:,:,1:5)

you can add another loop (iw=1:5;), store the errors in a vector: Er(iw,1).

Then

[value,index]=min(Er); %if Er is not a vector, then add the dimension (like Sean says)

w(:,:,index) gives you the matrix that minimized the error

something like that

4 Comments

Sargondjani on 11 May 2012

i didnt understand much of your question, really. because you said you 20 images, but you want to do it for 5 images.... to confusing for me...

so let's say we change 5 into 20, do you get it then?

i mean, you have to store the 20 images + errors. say im=1:20, so you have images(:,:,im) and errors(im,1).

then pick the minimum error with:
[value,index]=min(error)

now you have the index, so you just have to retrive the corresponding image: image(:,:,index)

do you understand the method???

kash on 11 May 2012

Sargondjani i think i did not explain you well,

1.i have 5 images,i am passing it to a loop,one by one

2.ten i am multiplying each image by the matrix A1_20(:,:,j1),where this matrix contains 20 matrix values of zeros and ones,

3.so for 1st image i get 20 matices.(images),in this i want to find the image having minimum error ..

4.finally i want to do for all 5 images

Sargondjani on 11 May 2012

do you understand my method??

i mean, i prefer not to spell out solutions, but to give exampls so you can figure out the details yourself :-)

Sargondjani

Contact us