2nd degree ODE with ode45

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Nina
Nina on 24 May 2012
Hello everybody,
this is a great occasion to explain MATLAB's ODE solving strategies to less experienced users like me.
I'm trying to solve a 2nd degree ODE u'' = (1/t)*u' - 4*(t^2)*u with ode45; on [1,20].
Inspired by the documentation for ode45, I tried:
function dy = rigid(x,y)
function ddy = rigid(x,dy)
dy = @(x) diff(y)
ddy = @(x) (1/x)*dy(x) - 4*(x^2)*y(x)
tspan = [1 20]
y0 = [sin(1)+cos(1); 1*cos(1)-1*sin(1)]
[X,Y] = ode45(@rigid,tspan,y0)
plot(X,Y)
which my MATLAB accepts without error messages, but doesn't produce any plot. Could you give me a hint what could be wrong?
Thank you!

Answers (1)

bym
bym on 24 May 2012
Well, pretty close. You need to define the ODE as a system of first order ODE's realizing the function arguments can be a matrix (example without using anonymous functions):
function dudt = rigid(t,x)
dudt = [x(2);x(2)./t-4.*t.^2*x(1)]; % function named rigid.m
in the script you would then use
tspan = [1 20];
y0 = [sin(1)+cos(1); 1*cos(1)-1*sin(1)];
[X,Y] = ode45(@rigid,tspan,y0);
plot(X,Y);
  4 Comments
Sean de Wolski
Sean de Wolski on 25 May 2012
I don't know about the error but you're not going to be able to stack two anonymous functions into a vector du. You will get and error on lines 6/7 for trying this.
Walter Roberson
Walter Roberson on 25 May 2012
Storing anonymous functions in [object] vectors used to be supported (but not in numeric vectors). But it led to ambiguous syntax, so now one is required to use cell arrays to store anonymous functions.

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