Hi all, A=[1;3;5; 6]; for 1 to 100 iterations, if any element in array matches with the iteration,e.g .for 1st iteration A's 1st data is matching. else it should come out from the loop. Can u suggest me any idea?
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for nn = 1:8 if(any(A==nn)), disp('hi'); else disp('bye'); end end
Obviously, replace disp('hi') with your calculation and I've just shown this up to an index of 8.