How to replace zeros in a matrix by the elements of an array?
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Hi everybody! I have a matrix (A) that contains zeros but it may contain also ones.
R=1:8; A=[1 0 0 0;
0 0 0 0;
1 0 1 1]
How to replace all the ones by zeros and all the zeros by elements of an array (R) going column-wise so that the resulting matrix (B) would look like:
B=[0 2 5 7;
1 3 6 8;
0 4 0 0]
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Accepted Answer
Thomas
on 6 Jun 2012
You are on the right track, though it can be done in much simpler way but since you are a beginner this will suffice..
use
Your input matrix was zeros, just add a count for R values
Editing your code:
A=[1 0 0 0;
0 0 0 0;
1 0 1 1]
D=3;
N=4;
% A=zeros(D,N);
equations=sum(A(:)==0);
R=1:equations;
count=1;
for j=1:N
for i=1:D
if A(i,j)==1
A(i,j)=0;
else
ID(i,j)=R(count);
count=count+1;
end
end
end
ID
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More Answers (1)
Image Analyst
on 6 Jun 2012
R=1:8;
A=[1 0 0 0;
0 0 0 0;
1 0 1 1]
linearIndices = A == 0
B = A; % Make a copy.
B(A==1) = 0
B(linearIndices) = R;
This is a vectorized way of doing it rather than your for loop method.
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