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Asked by mayuresh on 25 Jul 2012

sampling can be done to continous signal ,the signal after sampling can be given to discrete wavelet transforms for the further processing.how to find the energies of the function over the two cycle windows which are moving. please tell me and help me!!!!!!!!

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## 4 Comments

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/44496#comment_91494

Can you please explain what you mean by "two cycle windows"

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/44496#comment_91503

TWO CYCLE WINDOW MEANS ,ONE CYCLE FREQUENCY=60Hz,time=1/60 ok. then in one cycle window we can find the no. samples going to ocuppied in the one cycle ,and from that we can find the values of detail coefficients.

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/44496#comment_91510

I do not understand? The frequency tells you how many samples per cycle, so it is not clear why you would need two cycles?

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/44496#comment_93207

SIR ,i want to find the value over some time periods,i want to check some values.