How do I count the number of NaNs in a Vector?
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I have an nxm array a(n,m) with an unknown number of NaNs inside. I want to look for the column a(i,:) which contains the least number of Nans, how do I do this?
thank you for your help
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Accepted Answer
Daniel Shub
on 7 Aug 2012
This is a straight forward question and given you haven't shown any attempt to solve it, I am hesitant to provide an answer ...
Start by making some nonsense data
n = 10;
m = 5;
a = randn(n, m);
a(rand(numel(a), 1) < 0.25) = nan;
a =
0.5377 -1.3499 0.6715 0.8884 NaN
1.8339 3.0349 -1.2075 -1.1471 NaN
-2.2588 0.7254 0.7172 -1.0689 0.3192
NaN -0.0631 NaN -0.8095 0.3129
NaN 0.7147 0.4889 -2.9443 -0.8649
-1.3077 -0.2050 1.0347 1.4384 NaN
-0.4336 -0.1241 NaN 0.3252 -0.1649
0.3426 NaN -0.3034 -0.7549 0.6277
3.5784 NaN 0.2939 1.3703 NaN
NaN 1.4172 -0.7873 -1.7115 1.1093
The ISNAN function tells you if an element is a nan (1) or not (0).
isnan(a)
ans =
0 0 0 0 1
0 0 0 0 1
0 0 0 0 0
1 0 1 0 0
1 0 0 0 0
0 0 0 0 1
0 0 1 0 0
0 1 0 0 0
0 1 0 0 1
1 0 0 0 0
Now we want to sum up all the ones in each column. We have the SUM function that does that
sum(isnan(a))
ans =
3 2 2 0 4
To get the final answer we want to find which column has the smallest sum. The MIN function usually returns the smallest values, but if you read the documentation, the second output argument is the index of the minimum value.
[~, col] = min(sum(isnan(a)))
col =
4
where the ~ notation allows for the first output argument to be ignored.
More Answers (2)
Azzi Abdelmalek
on 7 Aug 2012
Edited: Azzi Abdelmalek
on 7 Aug 2012
s=sum(isnan(a)); %
[dd,ff]=min(s);
find(s==dd) % gives the rows that contain the least "nan"
% it's possible there are many rows containing the least nan
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