How to implement the following?
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How can I implement the following?
x(k + 1)= C [x(k); μ] = x(k)/μ ,if x(k) ∈ [0, μ)
(x(k)−μ)/(0.5−μ) , if x(k) ∈ [μ, 0.5)
C [1 − x(k); μ] , if x(k) ∈ [0.5, 1)
and k = 0,1,2,...n and 0<μ<0.5
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Accepted Answer
Azzi Abdelmalek
on 28 Aug 2012
Edited: Azzi Abdelmalek
on 28 Aug 2012
x=rand(10,1);mu=randi(49,1,1)/100+0.0001% example
for k=1:length(x)-1
if x(k)>=0 & x(k)<mu
x(k+1)=x(k)/mu
elseif x(k)>=mu & x(k)<0.5
x(k+1)=(x(k)-mu)/(0.5-mu)
elseif x(k)>=0.5 & x(k)<1
x(k+1)=(1-x(k))/mu
end
end
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