Is it possible to use non-constant Neumann boundary conditions with the parabolic pde solver?

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I am looking to solve the 2D heat equation T = T(r, theta, t) on a circle. I have a non-constant Neumann BC on the outside of the circle (r = a), where I have a heat flux as a function of theta (-k*dT/dx = q(theta) at r = a).
I know that I can decompose theta in to atan(y/x) -- in general though, I am unclear on how to use either the pdebound or assemb functions to prescribe these boundary conditions.
Thank you for your help!

Accepted Answer

Bill Greene
Bill Greene on 31 Aug 2012
Hi,
You are definitely on the right track in assuming that creating a pdebound function is a good way to define this BC. I created a simple example below that assumes you have an inward heat flux of 5*sin(theta), defines a pdebound function for this BC (I called it boundaryConditions), and then uses that to solve the heat equation on a circle. Hopefully this example will get you past some of the sticky issues.
Regards,
Bill
function transientHeatCircle( )
radius = 2;
gdm=[1 0 0 radius]';
g = decsg(gdm, 'C1', ('C1')');
[p,e,t]=initmesh(g);
c = 1; d = 2; a = 0; f = 0;
b = @boundaryConditions;
u0=0; tlist=0:.001:1;
u=parabolic(u0, tlist, b,p,e,t,c,a,f,d);
figure; pdeplot(p, e, t, 'xydata', u(:,end), 'mesh', 'on'); axis equal;
title 'Final Temperature Distribution'
n=4; %grid point at theta=pi/2
figure; plot(tlist, u(n,:)); grid on;
title(sprintf('Temperature at (%3.1f,%3.1f) as a Function of Time', ...
p(1,n), p(2,n)));
end
function [ q, g, h, r ] = boundaryConditions( p, e, u, time )
N = 1;
ne = size(e,2);
q = zeros(N^2, ne);
% calculate coordinates of edge mid-points
xy1 = p(:,e(1,:));
xy2 = p(:,e(2,:));
xyMidEdge = (xy1+xy2)/2;
g = 5*sin(atan2(xyMidEdge(2,:),xyMidEdge(1,:)));
h = zeros(N^2, 2*ne);
r = zeros(N, 2*ne);
end
  2 Comments
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Link on 31 Aug 2012
Thank you very much! That helps immensely in my understanding of how to use functions like pdebound.
If I had a second Neumann boundary condition defined on the same body, would I just concatenate it onto g? And similarly, a zero flux boundary condition at the center would be of the form g = 0 for all xyMidEdge points?
Bill Greene
Bill Greene on 2 Sep 2012
My code handled the simple case where you have a single BC expression that applies to all edges on the boundary. A more general version of a boundary function might look something like this.
function [ q, g, h, r ] = boundFunc( p, e, u, time )
N = 1; % number of PDEs in the system
ne = size(e,2);
q = zeros(N^2, ne);
g = zeros(N, ne);
h = zeros(N^2, 2*ne);
r = zeros(N, 2*ne);
for i=1:ne
ei = e(5,i);
if(ei == 1)
% apply appropriate BCs on edge 1
else if(ei == 3)
% apply appropriate BCs on edge 3
else if(ei == ...)
% apply appropriate BCs on this edge
end
end
end

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