using convolution with matlab
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x[n]=n^3-n^2, 0<n<3
h[n]=1/n, -2<n<-1
y[n] is the convolution of x[n] and h[n]
how can i compute y[n] ?
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Accepted Answer
Wayne King
on 21 Sep 2012
With all due respect, I think you need to take some time to read the MATLAB documentation.
n = 0:3;
x=n.^3-n.^2;
m=[-2:-1];
h=1./m;
y = conv(x,h)
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