Asked by Lucy
on 22 Sep 2012

Hi,

I'd like to superimpose a gaussian distribution over a histogram.

I am trying to use the histfit function, but following the histfit(x,n) format, where n is the number of bins, n must be a positive integer. I have (and must maintain) and value of n that is not an integer.

(I have to use a bin width of 0.5stdev of the data set. This results in me having 7.4623 bins.)

How do I overcome this problem?

Thx.

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Answer by Wayne King
on 22 Sep 2012

Edited by Wayne King
on 22 Sep 2012

Why do you say that you must have a number of bins that is not an integer? How can you have anything but a positive integer for the number of bins?

You can approximate pretty closely a bin width of 1/2*std(data)

data = randn(1000,1); binwidth = 1/2*std(x); numbins = round(range(data)/binwidth); % now construct a histogram just to check bin width [~,binctrs] = hist(data,numbins); % look at bin width mean(diff(binctrs)) % compare to 1/2*std(data) 1/2*std(data)

You should see there is very little difference between the bin width you want and what you get.

Now you can use that number of bins in histfit()

histfit(data,numbins)

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on 19 Sep 2013

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