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Asked by Passband Modulation
on 5 Oct 2012

a sound file with content consisting of 65120 rows of item as following shows

file source: http://www.2shared.com/document/LCmLelLW/message.html

where r[k] corresponds to message. say for example :

r[k] corresponds to the floating point number in first row of the file for k=0.

r[k] corresponds to the floating point number in second row of the file for k=1.

r[k] corresponds to the floating point number in third row of the file for k=2. and so on.

finally, r[k] corresponds to the floating point number in last row of the file for k=65119.

i want to plot s[k] using the following equation s[k]=r[k]-56.97cos(3.6k)-31.98sin(3.6k)

for k=0:length(message)-1

i tried, but again failed.

load message.txt N=65120; k=0:N-1; s = message - 56.97*cosd(3.6*k)-31.98*sind(3.6*k); s k=0:N-1; plot(k,s) xlabel('k');

could anyone help to fix? thx!

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Answer by Walter Roberson
on 5 Oct 2012

Accepted answer

load message.txt N=65120; k=0:N-1; s = message - 56.97*cosd(3.6*k.')-31.98*sind(3.6*k.'); %changed s %k=0:N-1; %no need to recalculate it plot(k,s) xlabel('k');

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