Asked by Edvardas
on 22 Oct 2012

Hello,

I am fairly new to Matlab and thought of using it for one project to plot some graphs. Problem is it requires Macaulay's notation. At the moment I've come up with a function file like this:

function [ V ] = Untitled2( x )

%UNTITLED2 Summary of this function goes here

% Detailed explanation goes here;

R1h= 632.568;

R2h= -2722.793;

Th= -2090.455;

A=x;

B=x-0.76;

C=x-0.99;

if A>0

A=1;

else

A=0;

end

if B>0

B=1;

else

B=0;

end

if C>0

C=1;

else

C=0;

end

V=R1h*A+R2h*B+Th*C;

plot(x, V);

end

Now, it gives the correct values for the shear force V whenever I add a specific coordinate x, however I can't think of a way for it to plot all the points. To be more precise I need it to be at V= 632.568 up until x=0.76, then it should go down straight to V= -2090.455 up until x=0.99 and then return to 0.

If any advice could be given about how to plot such a graph (or make better use of Matlab for Macaulay's notation) I would really appreciate!

Thanks!

*No products are associated with this question.*

Answer by Walter Roberson
on 22 Oct 2012

Remove the plot() statement. Then in a new driver routine use

V = arrayfun(@Untitled2, x); %x can be a vector plot(x, V);

Edvardas
on 22 Oct 2012

Thank you for such a quick reply!

It seemed to have worked halfway only though, the figure now seems to show the correct range of numbers on x and V axis, however it doesn't draw the graph itself. (Not sure if relevant, but used x as a matrix 0:0.01:0.99). So a little bit confused now, can anything be done about that?

Edit: Just noticed the negative x values, not sure why they're there, considering the matrix I added was from 0 to 0.99.

Answer by Matt Fig
on 22 Oct 2012

Edited by Matt Fig
on 22 Oct 2012

function [ V ] = Untitled2(x) V = zeros(size(x)); V(x<=.76) = 632.568; V(x>.76 & x<=.99) = -2090.455;

Now, from the command line:

x = 0:.001:1.5; plot(x,Untitled2(x))

Also, why not name your function some useful name, like:

function V = shearforce(x) V = zeros(size(x)); V(x<=.76) = 632.568; V(x>.76 & x<=.99) = -2090.455;

This 'Untitled2' business is just awful!

Edvardas
on 22 Oct 2012

Thanks! Works like a charm for shear force. Was hoping that it would be possible to do with my initial try, as that would be quite easy to transform into a bending moment function as well. Will try to figure out something along this path as well :)

And yes, good point with the naming, got too enthusiastic with Matlab whilst trying to figure out how to do the function, completely forgot about renaming!

MATLAB and Simulink resources for Arduino, LEGO, and Raspberry Pi test

Learn moreOpportunities for recent engineering grads.

Apply Today
## 0 Comments