on 23 Oct 2012

### Matt J (view profile)

floor(1.999999999999)=1 floor(1.99999999999999999999999999)=2, why is that?

Floor should return the lower integer right? Thanks.

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on 23 Oct 2012
Edited by Matt J

### Matt J (view profile)

on 23 Oct 2012

If that confuses you, this probably will too:

```>> isequal(1.99999999999999999999999999, 2)
```
```ans =
```
`       1`

Anyway, it has nothing to do with the FLOOR command. It's because your big long decimal can't be distinguished from 2 in floating point.

C Zeng

### C Zeng (view profile)

on 23 Oct 2012

Thanks a lot Matt!

Matt J

on 23 Oct 2012

Matt J

### Matt J (view profile)

on 23 Oct 2012

This one contains an overloaded floor function, if that's what you mean

http://www.mathworks.com/matlabcentral/fileexchange/6446-multiple-precision-toolbox-for-matlab

### Azzi Abdelmalek (view profile)

on 23 Oct 2012

Just try without floor

```a=1.99999999999999999999999999
```

Azzi Abdelmalek

### Azzi Abdelmalek (view profile)

on 23 Oct 2012

I am not sur what you mean by converting to 2 digits, I think, with 2 digits, you will have four possible digital numbers, And you need a min and max value to be able to do this conversion. Can you explain, or post another question?

Walter Roberson

### Walter Roberson (view profile)

on 23 Oct 2012

If you are starting with an integer, then dividing by a power of 2 can never result in this kind of round-off. Powers of 2 are represented exactly in binary floating point numbers, and dividing by a power of two effectively only changes the internal binary exponent without changing the mantissa. If you are running into this kind of round-off then either you are not starting with an integer or you are not dividing by a power of 2.

C Zeng

### C Zeng (view profile)

on 26 Oct 2012

Thanks, Walter, though I do not understand your point. I am transferring an integer like N to 2-digits. I want to divide it by 2 to determine if the entry is 0 or 1. Floor function does not make sufficient proximity to this problem.

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