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Curve fitting function (fit) error

Asked by sepideh
on 2 Nov 2012
Latest activity Answered by Di Xu
on 8 Sep 2016

I am using function "fit" to fit a surface to my data. I have a 3 dimentional data , z(x,y). I use the function as below: surfacefit=fit([x y],z,'polyll') I am sure both my x and y are column matrix and have the same dimension. But i get this error : Error using fit>iFit (line 133) Y must be a column vector.

Error in fit (line 109) [fitobj, goodness, output, convmsg] = iFit( xdatain, ydatain, fittypeobj, ...



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3 Answers

Answer by Walter Roberson
on 2 Nov 2012

surfacefit=fit([x(:), y(:)],z(:),'polyll') 


Hi, thanks for the answer, but i still get the same error.

Many Thanks for this answer

Answer by Kutsop
on 12 May 2016

I had the same problem. "Y" in this case is the second variable called in fit("X","Y","fittype") where for a 3D fit "X" is usually "[x,y]" and "Y" is "z" or in other words fit("[x,y]","z","fittype"). So if for z is a 64 by 64 array and x = 1:64; y = 1:64; then you need to make both x and y 64 by 64 arrays with repeated column and row values respectively, and then use reshape to make x,y,z all 4096 by 1 column vectors. You bassically need to unravel your 3D array.


Answer by Di Xu
on 8 Sep 2016


I think your z is a matrix, right?

But in fit([x y],z,'polyll'), z must be a column.

So you can use the reshape function You can simply reshape z into a column by z=reshape(z,[],1). Of course, you should accordingly change x and y, in order that they have the same disension as z, i.e. for every element in z, its coordinates should be at the according position in x and y.

Then you can run fit.


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