How do I solve m = 2 [1- (ln(1/A)-1)/N + ln ( (1+(c/Kon))/1+(c/Koff))) in MATLAB?
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I want to solve this equation:
m = 2 [1- (ln(1/A)-1)/N + ln ( (1+(c/Kon))/1+(c/Koff)))
when
A = 1/3
N =10
c= 0
Kon= 0.5
Koff = 0.02
How can i do it? I tried the solve function, but I can't do it.
2 Comments
Jan
on 23 Nov 2012
Edited: Randy Souza
on 29 Nov 2012
@dafdfad: Destroying the question after an answer is given does not meet the intention of this forum. It is a counter-productive method. Please stop this. I do not like this forum to be misused.
Randy Souza
on 29 Nov 2012
I have restored the original text of this question.
dafdfad, this question has a clear subject and an accepted answer, so it may be valuable to someone else in the future. If you have a good reason why it should be removed from MATLAB Answers, please flag the question, explain why it should be deleted, and an administrator or high-reputation contributor will consider deleting the question. Please do not simply edit your question away.
Accepted Answer
Image Analyst
on 20 Nov 2012
A few errors: no * after the 2, a square bracket instead of parenthesis, and ln instead of log. Corrected code:
A = 1/3;
N =10;
c= 0;
Kon= 0.5;
Koff = 0.02;
m = 2* (1 - (log(1/A)-1)/N + log( (1+(c/Kon))/1+(c/Koff)))
In the command window:
m =
1.98027754226638
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