How to make an efficient if-statement-expression that when identifying a 1x3 vector consisting only of either 6's,7's,8's or 9's gives the same statement?
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I could you run following if statement
vec=[9 9 9]; if vec(1:3)==9 | vec(1:3)==8 | vec(1:3)==7 | vec(1:3)==6 disp('Identified') end Identified
But is there not a more efficient way to accomplish this in stead of writing all these 'or-signs' in the if statement? With vectorized code? I have tried with a for loops, but got problems when writing it under an if statement with more than one evaluation option like elseif
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