## How to remove few data points from a MATRIX

### Jatin Arora (view profile)

on 23 Nov 2012

Hello Everyone ,

I have a set of points which are stored in n*3 MATRIX. These are points from a sensor and at the starting and ending there is a lot of disturbance in the signal and I get points which are very close to each other. I have to remove these points. So I check the distance between points starting from the first point and whenever I get a point outside a user input radius I break the loop.

The problem is I want to make a new array of dimensions m*3 in which I have the first point of my Input array then next (x) points are removed and then i get the remaining points.

Can someone help me with this?

Jatin Arora

### Jatin Arora (view profile)

on 23 Nov 2012

I would like to clarify that starting with n*3 Matrix I remove p*3 points and then in the final array should be like the first point followed with n-p points. The numer of coulmns remain 3 whatever the case maybe

Jan Simon

### Jan Simon (view profile)

on 23 Nov 2012

What exactly are "points" here? Are you talking about n points in the 3D space?

Posting an explicit example as Matlab code is more accurate than a text description.

Jatin Arora

### Jatin Arora (view profile)

on 29 Nov 2012

I would like to thank everyone who took time to read through my question and answer it. I woul like to say sorry as I could not reply due to some problem. After researching on the internet I found what exactly I want to implement.

I want to implement a Moving window filter in 3D space for cloud data of points.

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### Jan Simon (view profile)

on 23 Nov 2012

I'm not sure if I understood the concept of your "points" correctly. But perhaops you want something like this:

```X = cumsum(rand(1000, 3));  % Test data
keep = false(1000, 1);
```
```orig = X(1, :);
keep(1) = true;
for ii = 2:1000
dist_2 = sum((X(ii, :) - orig) .^ 2);
keep(ii) = true;
orig     = X(ii, :);
end
end
CleanedX = X(keep, :);
```

Image Analyst

### Image Analyst (view profile)

on 24 Nov 2012

I'd think you'd do

```if dist_2 <= radius_2
```

because he wants to keep only those within that distance of the first point, not keep points farther away.

Jan Simon

### Jan Simon (view profile)

on 25 Nov 2012

Perhaps you are right, I.A. (is the abbreviation ok? After all these years I still hesitate to call you like your profession). I thought this means the opposite: "... I get points which are very close to each other. I have to remove these points."

Image Analyst

### Image Analyst (view profile)

on 25 Nov 2012

You can call me IA - no problem. I read it as he had sensor points (3D coordinates as rows in his n*3 array) and the several rows at the top and bottom were from the sensor and they were good. The stretch in the middle were bad points "with a lot of disturbance" and he didn't want those points (rows). So he wanted to check which points were close to the very first point (which was assumed to be good), and keep those (perhaps extracted into a new array) and discard the rest. When he said "have the first point of my Input array then next (x) points are removed and then i get the remaining points." I took that to mean keep the first few good points at the beginning, remove the bad points in the middle, and keep the remaining good points at the end. But it's not totally clear and he should clarify.

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