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Creating cell array of strings in a loop

Asked by Craig on 4 Dec 2012

Hi all,

I have a few lines as such:

timeStrings = cell(1,entries_per_variable);  
for o = 1:1:entries_per_variable
timeStrings{o,1} = [num2str(TimeValue(3,o),'%02i'),'/', num2str(TimeValue(2,o),'%02i'),'/', num2str(TimeValue(1,o),'%04i'),...
' ',num2str(TimeValue(4,o),'%02i'),':',num2str(TimeValue(5,o),'%02i'),':',num2str(TimeValue(6,o),'%02i')]; %this be a column vector
end

It basically converts some values in TimeValue to strings, adds some spaces and slashes using the [] string catenation method and puts them in a new cell array.

I'm running out of memory less than 50 entries in! As you can see the memory is preallocated so I can't fathom why.

Best regards,

Craig B

1 Comment

Jos (10584) on 4 Dec 2012

... you pre-allocate a 1xN array, but intend to fill a Nx1 array, ending up filling a NxN array ... (This should not give you memory problems though)

I also suggest you take a look at SPRINTF.

Craig

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1 Answer

Answer by Craig on 4 Dec 2012
Accepted answer

Ok I got the dimensions of the preallocation wrong. Should have been timeStrings = cell(entries_per_variable,1);

Best regards,

Craig

0 Comments

Craig

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