for i=1:5 filename_1 = ['E:\Abhi\file_',num2str(i)]; save (filename_1) end
for j=1:9
filename_1 = ['E:\Abhi\file_',num2str(j)];
exist('filename_1','file') % not sure how to write this exactly
end
here I expect to get answer 2 for file_1 to file_5 and for rest others as 0.
Thanks.
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Did you try it? The help for EXIST indicates you can use it as you are doing.
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