Inverse Laplace and plotting system respone

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Rok
Rok on 16 Dec 2012
Hello, I am having some issues with plotting function I get from inverse Laplace transformation. It is a linear controlling system with input step signal.
syms s
A = 1+1/(103*s);
B = (0.33/s)/(1-0.33/s);
C = 0.0875/s;
n = A*B*C;
d = 1 - (A*B*C);
r = 1/s; %step function
tf = (n/d)*r
h = ilaplace(tf)
ezplot(h, [1,1000]), axis square, grid on
This is what i get.
tf =
-(231*(1/(103*s) + 1))/(8000*s^3*((231*(1/(103*s) + 1))/(8000*s^2*(33/(100*s) - 1)) + 1)*(33/(100*s) - 1))
h =
- 8240*sum(-(33*r3*exp(r3*t) - 100*r3^2*exp(r3*t))/(- 2472000*r3^2 + 543840*r3 + 23793), r3 in RootOf(s3^3 - (33*s3^2)/100 - (231*s3)/8000 - 231/824000, s3)) - 1
??? Error using ==> char
Cell elements must be character arrays.
Error in ==> ezplot at 158
fmsg = char(f);
Error in ==> sym.ezplot at 56
h = ezplot(char(f),varargin{:});
Error in ==> laplace2 at 26
ezplot(h, [1,1000]), axis square, grid on
>>
Can please someone help me with that? I have to plot the system response.
Thanks.

Answers (1)

Walter Roberson
Walter Roberson on 19 Dec 2012
Try
ezplot(matlabFunction(h), [1,1000])
or just
t = linspace(1,1000,500); %500 is number of samples to plot
hfun = matlabFunction(h);
plot(t, hfun(t));

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