representing 8 bits per element

In the previous post

walters comment

Remember, comp is representing binary, and so is 1 bit per element, whereas your original data is at least 8 bits per element.

now how to represent binary element as 8 bits per element

binary values are stored in comp

Why wasn't this posted in that previous post then? Why did you start a whole new discussion?

Answer 1

Provided your vector comp is an exact multiple of 8 long:

x = comp;  %just to make the writing shorter

uint8( x(1:8:end) * 128 + x(2:8:end) * 64 + x(3:8:end) * 32 + x(4:8:end) * 16 + x(5:8:end) * 8 + x(6:8:end) * 4 + x(7:8:end) * 2 + x(8:8:end) )

walter i get error

??? Error using ==> plus Matrix dimensions must agree.

size(x)

ans =

      167770           1

till x(2:8:end) * 64;

the size is

20972           1

after that the size is

20971           1

As I said, "Provided your vector comp is an exact multiple of 8 long"

If it isn't, then pad it with zeros.

walter every time the size is varying

while length(x) ~= 8 * floor(length(x)/8)
  x(end+1) = 0;
end

thanks a lot