Asked by FIR
on 27 Dec 2012

In the previous post

walters comment

Remember, comp is representing binary, and so is 1 bit per element, whereas your original data is at least 8 bits per element.

now how to represent binary element as 8 bits per element

binary values are stored in comp

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Answer by Walter Roberson
on 27 Dec 2012

Accepted answer

Provided your vector comp is an exact multiple of 8 long:

x = comp; %just to make the writing shorter

uint8( x(1:8:end) * 128 + x(2:8:end) * 64 + x(3:8:end) * 32 + x(4:8:end) * 16 + x(5:8:end) * 8 + x(6:8:end) * 4 + x(7:8:end) * 2 + x(8:8:end) )

Show 3 older comments

FIR
on 27 Dec 2012

walter every time the size is varying

Walter Roberson
on 27 Dec 2012

while length(x) ~= 8 * floor(length(x)/8) x(end+1) = 0; end

FIR
on 27 Dec 2012

thanks a lot

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## 1 Comment

## Image Analyst (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/57470#comment_119419

Why wasn't this posted in that previous post then? Why did you start a

whole newdiscussion?