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How to find out the image center?

Asked by Naresh Naik on 31 Dec 2012

How to find out the image center and its x,y co-ordinate with out using [x,y]=ginput(n) matlab command?

How to import these data into matlab work space?

EX. image http://img839.imageshack.us/img839/2002/bull1.jpg

Naresh Naik

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2 Answers

Answer by Matt J on 31 Dec 2012
Edited by Matt J on 31 Dec 2012
Accepted answer
 A=rgb2gray(imread('bull1.jpg'));
 center=size(A)/2+.5;

0 Comments

Matt J
Answer by Walter Roberson on 31 Dec 2012

imfill(), then regionprops() the Centroid

6 Comments

Naresh Naik on 31 Dec 2012

Sir here i did thresh,im2bw,imfill and finally i got this image.

http://imageshack.us/photo/my-images/600/imfill.jpg/

My only application is finding out the width of the circle by single mouse click only ,up to now whatever you suggested is more than two mouse pointer clicks. for the above link circle if we find out the width in pixel using only one click almost my application will be completed so please guide me.

Walter Roberson on 31 Dec 2012

Not me. I suggested the no-mouse-click version that finds all of the information at the same time. I also showed how to select the information for a single one out of that: namely, use label the binary image, regionprops() the information out, then use ginput() on the original image to select a point, look up that point in the label image to find the index into the regionprops struct() information, return the appropriate result.

Image Analyst on 31 Dec 2012

You need to invert that image. The foreground has to be white, not black.

FYI, in the duplicate question here, Naresh first asked for a method using ginput(). Walter suggested an automated way using regionprops(), but then Naresh again asked for a manual method using ginput(), which I gave. Now I guess Naresh is willing to consider the automatic method again, for which code is in the first question. An example of finding centroids of round objects (coins, not rings) can be found in BlobsDemo image segmentation tutorial in my File Exchange.

Walter Roberson

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