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Help on interp3 function (meshgrid compatibility error on input data)

Asked by AP on 2 Jan 2013

Dear All,

I am trying to use interp3 for my data which can be found at http://www.mathworks.com/matlabcentral/fileexchange/?term=authorid:73338. The file is about 7MB. The data is distributed over an ordered Cartesian grid with uniform intervals. I can successfully use stream3 by adjusting the data for meshgrid compatibility according to the following code using permute function. It works fine. However, when I want to do interpolation, I get an error which says the input data is not a valid meshgrid.

x         = permute(x        , [2 1 3]);
y         = permute(y        , [2 1 3]);
z         = permute(z        , [2 1 3]);
u         = permute(u        , [2 1 3]);
v         = permute(v        , [2 1 3]);
w         = permute(w        , [2 1 3]);  
InOut     = permute(InOut    , [2 1 3]); 
[ sx, sy, sz ] = meshgrid( -1:1:1, -1:1:1, -1:1:1 );
vertices = stream3( x, y, z, u, v, w, sx(:), sy(:), sz(:) );
val = interp3( x, y, z, InOut, 0, 0, 0 );

The above code stops at the line where I do the interpolation. Could someone help me?

Thanks, Ahmad

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AP

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1 Answer

Answer by Walter Roberson on 2 Jan 2013

Although error messages from the interp functions complain about needing meshgrid format, I find that in practice it is ndgrid() format that they need.

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Walter Roberson

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