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identify valid and invalid image

Asked by Elysi Cochin on 5 Jan 2013

i execute a code and get two types of output.... one is valid and the other is invalid.... the valid output image has content content in it.... whereas the invalid image is totally black....

based on this information what can i do to display a message that the image is valid or invalid.... some condition check so that i can display the message correctly.... please can someone reply.....

0 Comments

Elysi Cochin

1 Answer

Answer by Walter Roberson on 5 Jan 2013
Accepted answer
if ~any(TheOutputImage(:))
  msgdlg('Outside of a dog, a book is man''s best friend. Inside of a dog, it is too dark to read.');
else
  ......
end

4 Comments

Walter Roberson on 5 Jan 2013

The first thing you need to do is stop using "image" as a variable name: doing so makes it difficult to use the function image()

Second, if your code is not giving you the message box, then the output is not "totally black" as you claimed. Find out what

max(YourImage(:))
mean(YourImage(:))
std(YourImage(:))

are for the invalid images.

Elysi Cochin on 5 Jan 2013

sir i got it... thank u sir... i wrote the display outside the for also... thank u sir...

Walter Roberson on 5 Jan 2013

Put a breakpoint in at the "if ~any" and run your code again with something that creates an invalid image. Single-step through the code. I think you will find that the black image is not displayed by this section of code. If you continue single-stepping you will find the place that is displaying it.

Walter Roberson

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