Discover MakerZone

MATLAB and Simulink resources for Arduino, LEGO, and Raspberry Pi

Learn more

Discover what MATLAB® can do for your career.

Opportunities for recent engineering grads.

Apply Today

Problem in Gray Level Manipulation

Asked by Vennila on 6 Jan 2013

Hi all,

I tried to enhance a gray scale image by using the formula

   E(i,j) = round( I(i,j)^3/ f * M^2)

where

      M = max gray level of the image
      f = 0.8

The output should be a gray scale image, but I get a binary Image.

Thanks for your help in advance.

Code :

[x,y] = size(I);
I1 = repmat(uint8(0),x,y) 
M = max(I(:));
for i = 1:x
    for j = 1:y
        if I(i,j) ~= 0
          v = double(I(i,j));
          I1(i,j) = round( v^3 / f * M^2 );
          % disp(I1(i,j)); ' all manipulated pixels has value 255
        end 
    end
end

0 Comments

Vennila

2 Answers

Answer by Image Analyst on 6 Jan 2013
Accepted answer

What are some values of z? Also, have you looked at I1 in the variable editor to verify that they're all 255 or 1? Have you tried to display I1 with [], like this:

imshow(I1, []);

which you need to do for floating point images? M^2 is in the numerator - is that what you want? The units seem all weird - you'll have an output that is proportional to gray level to the fifth power! Are you missing some parentheses? Like you want M^2 in the denominator? Where did you ever get this formula anyway? Do you have a citation for it?

11 Comments

Image Analyst on 7 Jan 2013

Is f and array? It should be. But you're not using ./, you're using /, so that leads me to think that f is not an array like it needs to be.

Vennila on 7 Jan 2013

f is not an array.

Image Analyst on 7 Jan 2013

Then you're not following the algorithm given in the paper.

Image Analyst
Answer by Walter Roberson on 6 Jan 2013

Change

M = max(I(:));

to

M = double( max(I(:)) );

1 Comment

Vennila on 6 Jan 2013

I tried it but no change.

Walter Roberson

Contact us