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Square Gridlines in figure

Asked by Jonas on 14 Jan 2013

I generate with a loop several 2D figures out of data stored in a matrix. The figures have aerodynamic backround so it's indispensable to get squared gridlines. In this context "square" means that the distance between the horizontal and vertical gridlines are the same.

My idea: The lines which belong to the y-axis pretend the distance for the x-grid. But I have no idea to realize this... Can anyone help me?

  1. Boundary conditions:
  • all figures are 2D
  • data are stored in a 5D-matrix
  • y-axis: range from 0 to 1 with 0.05 steps, fix for each figure!
  • x-axis: range varied in each figure (according to data range stored in 5D matrix)
  • fix size/format of each figure: DIN-A5
  1. Examples of the plotted figures (gridlines are not squared!):

http://s7.directupload.net/file/d/3135/gvsi25mg_jpg.htm

http://s7.directupload.net/file/d/3135/yt4v4ml8_jpg.htm

Thanks for your help in advance!

1 Comment

Jan Simon on 14 Jan 2013

How does your "plot" look exactly? I assume the number of dimensions of your data matrix is not relevant, but it matters if you have a 2D or 3D plot. Does "square" mean, that the grind lines have the same numerical distance, or should they appear with the same width and hight in the printed output?

Jonas

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3 Answers

Answer by Image Analyst on 14 Jan 2013

I know it seems obvious, but since you didn't mention it, have you used the "grid on" command? If so, tell us why the "grid on" command does not work for you.

1 Comment

Jonas on 14 Jan 2013

Thanks for your comment. As you can see at the two examples in my answer on Jans comment above, I used "grid on". But the grid is rectangular and the size of the grid varied from figure to figure - the rectangles have in every figure another size.

Image Analyst
Answer by Jan Simon on 15 Jan 2013

The shown pictures seem like you want to get the ticks in equidistant steps in X- and Y-direction. Then the sections do not look like squares on the paper. Correctly?

X = linspace(0, 100, 10);
Y = rand(1, 10) * 100;
AxesH = axes;
plot(X,Y);
XL = get(AxesH, 'XLim');
YL = get(AxesH, 'YLim');
set(AxesH, 'XTick', XL(1):10:XL(2), ...
           'YTick', YL(1):10:YL(2));

Does this help?

1 Comment

Jonas on 15 Jan 2013

Hey Jan,

thanks for posting. The equidistant steps on the X-axis result from the data within the matrix. Matlab calculated these steps with the default settings (these are measured values). On the Y-axis you can see the different measurement points (mostly in equidistant steps). So your example has unfortunately not helped.

The equidistant steps in X- and Y-direction doesn't matter. Important are the squared looking sections on the paper (with given steps on y-axis).

Thanks again!

Jan Simon
Answer by Jan Simon on 19 Jan 2013

You can try to set the position of the axes object in absolute units 'centimeters'. Then you have more control over the output to paper. But even then more experiments are required and there is no trivial solution.

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Jan Simon

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