## Help me about looping in matlab

on 19 Jan 2013

### Matt J (view profile)

hello all,,

i've some problem in matlab's code especially in looping

my example like this ,,

i've two examples of data

```First | Second
```
```8	| 9
```
```7       | 8
```

New data : (6 6)

and then i wanna insert that data into a formula and that data would be like this

```x = (First Data - New Data(1))² + (Second Data - New Data(2))²
```

Example :

```x1 = (8 - 6)² + (9 - 6)²;
```
```x2 = (7 - 6)² + (8 - 6)²;
```

but i'm so confused about looping in matlab.

I don't know how to convert that formula into matlab's code.

this is my code

```%----------I N P U T----------------------
```
```a= input ('Input Number of Data :');
```
```for c=1:a
```
`    int2 = ['Input The First Score - ',num2str(c),' :'];`
`    int3 = ['Input The Second Score - ',num2str(c),' :'];`
`    b{c,1} = input(int2);  `
`    b{c,2} = input(int3);`
```end;
```
```d = cell2mat(b);
```
```for i=1:c
```
`      for j=1:2`
`          x(i,j)=??????????????`
`      end`
```end
```
```disp(x)
```

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### Matt J (view profile)

on 19 Jan 2013

No need to use cells for b, and you should pre-allocate it as well:

`    b=zeros(a,2); %pre-allocate!!`
```    for c=1:a
int2 = ['Input The First Score - ',num2str(c),' :'];
int3 = ['Input The Second Score - ',num2str(c),' :'];
b(c,1) = input(int2);
b(c,2) = input(int3);
end;```

There's also no need to use a loop to compute x. You can do it in one line as follows

```x = ( b(:,1) - NewData(1)).^2 + (b(:,2) - NewData(2)).^2;
```

Matt J

### Matt J (view profile)

on 19 Jan 2013
``` [~,r]=sort(First+Second,'descend');
Rank(r)=1:a;```
baby

### baby (view profile)

on 19 Jan 2013

sorry,,

i don't understand with ur code above

can u explain me what's mean "First+Second" and 'Descend'?

Matt J

### Matt J (view profile)

on 19 Jan 2013

Explain "the total of the lowest score"

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