Asked by Serhat
on 30 Jan 2013

Hi,

I am trying to calculate this integral.

sigmaZ= -0.1464*eye(4);

f = @(x)(arrayfun(@(x)(1./(det(sigmaZ./sin(x).^2 + eye(4)))),x))

out = (1/pi)*quad(f,0,pi)

but it gives this result 3e+10. It must not have been that high. Is my integral wrong?

Thanks:)

*No products are associated with this question.*

Answer by Teja Muppirala
on 30 Jan 2013

Accepted answer

When sigmaZ is negative, the integrand blows up around x = 0.3 and x = 2.7 and you have a singularity which you cannot integrate.

For example, just plot it:

sigmaZ= -0.1464*eye(4); f = @(x)(arrayfun(@(x)(1./(det(sigmaZ./sin(x).^2 + eye(4)))),x)) ezplot(f)

When sigmaZ is positive, the integrand is always finite for x in [0 pi] and so you don't get any problem.

Answer by Jan Simon
on 30 Jan 2013

Is there any chance that we can guess what you want to calculate?

Jan Simon
on 30 Jan 2013

@Serhat: All you have shown us is the code and you explain, that it could be wrong. But we cannot suggest an improvement, when you do not explain, which equation this code should solve. And if this is still not clear, a simplified version:

I have c = a + b, where a is 2 and b is 3. I get the result 5, but I want 6. Where is the error?

Without a magic crystal ball it is impossible to find an answer.

Opportunities for recent engineering grads.

## 0 Comments