Output derivative for lookup table

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Benjamin Tay
Benjamin Tay on 11 Feb 2013
Hello everyone
I have input (x) and output (y) data vectors, but instead of outputting the data value y, I want the the Simulink block to output the derivative (dy/dx) instead.
Can this be achieved?
Ben
(PS: Here's what I tried. Take the time derivative dy/dt. And the time derivative dx/dt. Divide the two, get dy/dx. But, as a trial, I tried putting a horizontal y data vector for a monotonically increasing x data vector. In this case dy/dx should always be zero. Simulink gave me an error because they detected NaN at time t=0)
  1 Comment
Kaustubha Govind
Kaustubha Govind on 14 Feb 2013
Could it be because dx/dt=0 at t=0? Can you plot both values individually without the division to verify this.

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