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Answer by Image Analyst
on 13 Feb 2013

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Hint: use poly2mask() and logical indexing.

yourImage = zeros(rows, columns, 'uint8'); % Initialize. % Assign values to triangle defined by "mask" image. yourImage(mask) = someValue;

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Thanks. Using patch() did create the triangle. But with only one color.

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Well, did I *say* to use patch()? Looks like you need more hints. Create red, green, and blue channels

color1 = [100 150 200]; redChannel = color1(1) * ones(rows, columns, 'uint8'); % Display it imshow(redChannel); % Draw mask, for example, call roipolyold().

Then mask it like I said, then combine them all together into an rgb image:

rgbImage = cat(3, redChannel, greenChannel, blueChannel); imshow(rgbImage);

See if you can complete the script on your own.

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You are right. I still need more hints.

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Here is it practically done. Just 4 more lines and it's complete. You don't want me to do it completely for you do you? Would that be considered acceptable/ethical in your course?

color1 = uint8([100 150 200]); color2 = uint8([180 50 250]); rows = 480; columns = 640; redChannel = color1(1) * ones(rows, columns, 'uint8'); greenChannel = color1(2) * ones(rows, columns, 'uint8'); blueChannel = color1(3) * ones(rows, columns, 'uint8');

% Get/assign triangle vertices, triangleX, triangleY. % I'm sure you can figure out what goes here!

% Create mask. mask = poly2mask(triangleX, triangleY, rows, columns); % Display mask subplot(1,2,1); imshow(mask); % Assign values to triangle defined by "mask" image. redChannel(mask) = color2(1); % I'm sure you can figure out what goes here! rgbImage = cat(3, redChannel, greenChannel, blueChannel); subplot(1,2,2); imshow(rgbImage);

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You got your 2 color triangle like you wanted. The left triangle is just the mask I made with poly2mask(). Here, I've put in some title's to explain that:

color1 = uint8([100 150 200]); color2 = uint8([180 50 250]); rows = 480; columns = 640; redChannel = color1(1) * ones(rows, columns, 'uint8'); greenChannel = color1(2) * ones(rows, columns, 'uint8'); blueChannel = color1(3) * ones(rows, columns, 'uint8');

% Get/assign triangle vertices, triangleX, triangleY. % I'm sure you can figure out what goes here! triangleX = [0 100 200]; triangleY = [0 200 0];

% Create mask. mask = poly2mask(triangleX, triangleY, rows, columns); % Display mask subplot(1,2,1); imshow(mask); title('This is the mask poly2mask made', 'FontSize', 25); % Assign values to triangle defined by "mask" image. redChannel(mask) = color2(1); greenChannel(mask) = color2(2); blueChannel(mask) = color2(3); rgbImage = cat(3, redChannel, greenChannel, blueChannel); subplot(1,2,2); imshow(rgbImage); title('This is your triangle', 'FontSize', 25); % Enlarge figure to full screen. set(gcf, 'units','normalized','outerposition',[0 0 1 1]); % Give a name to the title bar. set(gcf,'name','Demo by ImageAnalyst','numbertitle','off')

If you want, you can just get rid of the first subplot() and imshow(). This solves your problem, so go ahead and mark it "Accepted."

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Walter Roberson
on 15 Feb 2013

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**we're back to two triangles of a single color each** and you can use my code. If that's still not what you want you'll have to upload a picture somewhere of exactly what you want (mock something up in Photoshop if you have to), because we're wasting a lot of time doing your homework for you and getting nowhere.

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Each half of the triangle must be in a different color. Is that clear enough?

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That's just two triangles stuck together. Can you tell me it isn't?

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They must be shown as 1 triangle....1 image.

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That's fine if you can not do it. You did not solve it by any means. I was just asking a question.

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*I* cannot do it. It's way beyond my skill set. Perhaps I need to re-enroll in graduate school.

Walter Roberson
on 15 Feb 2013

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You didnt solve it after all.

Walter Roberson
on 15 Feb 2013

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Cesar, you need to look more carefully at the image you supplied. Zoom in on the area near the tip. You will notice a few things:

- There appear to be three tips. The left tip is white, the center tip is white, the right tip is dark.
- The dark tip is part of a dark line that is most easily explained as if the dark line is the shadow of the center tip with respect to a light source that is to the left of center of the image.
- If the left (white) tip and center (white) tip were at equal heights, then both would have shadows, but there is only one shadow
- The details of the edge crossings of the left and center tips strongly suggest the interpretation that the left triangle is on top of the right triangle, with the left triangle ending a small bit to the right of the right triangle.
- the bottom line of the triangles show that the triangles continue to be overlapped all the way down

Together these make clear that this is **not** one bi-colored triangle: this is **two** triangles with no vertices in common.

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**I need 1 triangular image with height of 200 pixels and the base of 200 pixels colored with any two colors.** Please read the description. Do not focus on the picture I sent. You either can solve it or not.

Walter Roberson
on 16 Feb 2013

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*twice*, with different parameters each time, might accomplish the entire task.

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*not* solve it (supposedly I don't know how). I did way too much already, and it's such a trivial chore to finish it. Like Walter and I said, just do it twice. You said that half the triangle was one color and the other half was a different color. Now, ask yourself "What shape is half a triangle?" But ultimately it's your problem, not ours, and we *should not* do 100% of it for you, and I won't. There needs to be some part of it that *you* own, that *you write* yourself. You have all the tools, so, good luck with that.

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I did solve it. This is how it should look: https://www.dropbox.com/s/gsgcsb8rqwlg55z/done.doc

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Using fill(X,Y,C). The fill function creates colored polygons.

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