## Integrating a multivariate function w.r.t. a single variable

### Alexandru (view profile)

on 13 Feb 2013
Latest activity Answered by Yang Zhang

on 15 Mar 2015

### Teja Muppirala (view profile)

Hello,

I am defining a function using

f = @(x,y) (expression in x and y)

This definition I believe it is correct as I can call f(0,0) for example and I get the numerical value.

What I need to do next is integrate f(x,y) with respect to y between a and b and call this g(x). I need then to be able to pass g(x) to fsolve in order to compute the roots. How do I do this? I tried dblquad, but it integrates w.r.t. both variables at once. quad gives me and error as I am not sure what's the correct syntax for this.

Thanks, Alex

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### Teja Muppirala (view profile)

on 14 Feb 2013

Define another function handle to be the integral over y. Like this:

```% Just making some random 2d function
f = @(x,y) (x.^2-y.^2).*cos(x./(1+y.^2));
```
```% Some limits of integration
a = 0;
b = 3;
```
```% Define g as the integral of f(x,y) dy from a to b
g = @(x) integral(@(y) f(x,y) , a,b);
```
```% Plot it, and find a zero
ezplot(g)
fzero(g,0)
```

### Walter Roberson (view profile)

on 13 Feb 2013

You cannot do this with numeric integration.

If you have the symbolic toolbox, then expression the function symbolically and do symbolic integration with int(). Then if you need, you can use matlabFunction to turn the symbolic result into a function handle of a numeric function.

### Youssef Khmou (view profile)

on 13 Feb 2013

Hi, try this :

``` syms x y
h=exp(-x^2-y^2)
F1=int(h,x)
F2=int(h,y)```

Based on F1 and F2 you make function handle :

` Fx=@(x) 1/2/exp(x^2)*pi^(1/2)    %  truncated ERF(Y)`
` Y=fsolve(Fx,0.1)`

Walter Roberson

### Walter Roberson (view profile)

on 13 Feb 2013

How do you get from the "F1 and F2" to the Fx ? And where do the limits of integration over y come in?

Youssef Khmou

### Youssef Khmou (view profile)

on 13 Feb 2013

Hi,i used the undefined integration or "primitive" , for F1 you get :

```F1 =
```
` 1/2/exp(y^2)*pi^(1/2)*erf(x)`

you have an analytic integration w.r.t. x, so its function of y , now manually you set a function handle Fy :

` Fy=@(x) 1/2/exp(y^2)*pi^(1/2)`

and then solve it with "fslove" as Alexandru said he wants to use "fslove" .

### Yang Zhang (view profile)

on 15 Mar 2015

Use Symbolic Math Toolbox to your problem.

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