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Asked by Rooy
on 14 Feb 2013

When p=0;

I have to use a loop to flip the value of p between 0 and 1 and each time it has to be different in a single line of code.

Thank you

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Answer by Image Analyst
on 15 Feb 2013

Accepted answer

Is this what you're looking for?

p=0; for k = 1 : 5 % Here's the iterative loop it requested clc; % Here's the single line p = ~p pause(1); end fprintf('Done with demo!\n');

Image Analyst
on 15 Feb 2013

That also works for *any* value or p in between 0 and 1, like I asked about in my comment way up at the top. So perhaps this is the *most* general solution.

Answer by Youssef KHMOU
on 14 Feb 2013

Edited by Youssef KHMOU
on 14 Feb 2013

your_vector=mod(0:1000,2); % single line code

for i=1:length(your_vector)

% YOUR CODE fprintf('%d\n',your_vector(i)) pause(0.3) end

## 2 Comments

## Image Analyst

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/63529#comment_129681

What does the "When p=0;" mean? You only have to flip when p=0???

When you say "flip the value of p between 0 and 1" does that mean that p is either 0 or 1 only, or does it mean p can have a value between 0 and 1, like p=.426973 and flipping means inverting like flipped_p = 1-p?

## Rooy

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/63529#comment_129813

This was the question given : Write a MATLAB program that will start with the variable p=0. After the initial assignment to p, have a loop flip the value of p between 0 and 1, changing it once each loop iteration USING A SINGLE LINE OF CODE. [HINT: This is a math challenge.] Display it each iteration, using the pause() function to stop the loop temporarily each iteration

Thank you everyone for all the help