How to compare two arrays?

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Micky
Micky on 28 Feb 2013
Example:
aa = [1 1 1 1 -1 -1 1 1 1 1 1 1 -1 -1 1]
and
bb = [NaN NaN NaN NaN 0.2 0.3 NaN 0.2 0.3 NaN NaN NaN 0.2 0.3 NaN]
and I want to generate third array such that it contains values in bb for every value that correspond to -1 in aa, and for every other value I should get NaN, and the size of resulted should remain same as aa and bb. So the result should look something like this:
cc = [NaN NaN NaN NaN 0.2 0.3 NaN NaN NaN NaN NaN NaN 0.2 0.3 NaN].
I am doing something like this:
cc = bb(aa == -1 | isnan(bb));
But the length or the size of the array changes.
Please advice.

Accepted Answer

Image Analyst
Image Analyst on 28 Feb 2013
Try this:
cc = nan(1, length(bb))
cc(aa==-1) = bb(aa==-1)
In the command window:
cc =
NaN NaN NaN NaN 0.2000 0.3000 NaN NaN NaN NaN NaN NaN 0.2000 0.3000 NaN
  1 Comment
Micky
Micky on 28 Feb 2013
Thank you Image analyst. Both of the responses are almost similar.

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More Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 28 Feb 2013
Edited: Azzi Abdelmalek on 28 Feb 2013
cc=nan(1,numel(aa))
idx=find(aa==-1)
cc(idx)=bb(idx)

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