How do I calculate an infinite series using a function file with for-end loops?
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Given f(x)= [(x^2)/37]+[(x^3)/3!]+[(x^4)/4!]+[(x^5)/5!]+...
Using a function file (function fn=my_fun(x,n)) with for-end loops for several test files.
I'm just having issues defining the function file using the for-end loop. What I have so far is:
function [xval,nterms]=my_series(x,n)
3 Comments
Walter Roberson
on 3 Mar 2013
Could you confirm that the first term is divided by 37, and not factorial(2) as would match the 3! 4! 5! pattern?
Accepted Answer
Youssef Khmou
on 3 Mar 2013
hi gordon,
you function returns a scalar or vector values ? is this exp(x) Taylor series ?
you can try this light version :
function [xval]=your_series(x,n)
% X is vector input
% n number of iteration
xval=zeros(size(x));
order=0:n;
for ii=1:length(x)
for t=1:length(order)
xval(ii)=xval(ii)+(x(ii)^t)/factorial(t);
end
end
This function approximates well the EXP FUNCTION, replace the term ( x(ii)^t/t! ) with your general Formula .
3 Comments
Youssef Khmou
on 3 Mar 2013
Edited: Youssef Khmou
on 3 Mar 2013
if it is a scalar then :
% given scalar x
S=0;
S=(x^2)/37;
for ii=3:N
S=S+((x^ii)/factorial(ii));
end
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