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Can someone show me how I get the answer surrounded by the phrases in quotes through using the disp and num2str functions?

Asked by Brian on 4 Mar 2013
The maximum height achieved by an object thrown with a speed v at and angle of (Theta) to the horizontal, neglecting drag is 
h=((v^(2))*((sin^2)*(theta))/2*g
use g=9.81m/s^2 and create  a script file that lets the use enter a value of V(in m/s) and a value of theta(in degrees), and computes the maximum height h. 
Use the input function twice to prompt the user to enter values for v and theta.  The first prompt should say "Please enter a value of the initial velocity in m/s and then press enter". The second prompt should say "Please enter a value of the launch angle in degrees, then press enter".  
Use the disp function and the num2str function to display the numerical value of the height h with the text " The maximum height is:" followed by the value of of the launch angle in degrees, followed by the text "meters."
Use the script file to compute the maximum height when v=18m/s and theta=70 degrees.  

I understand how to do the problem up until the point where I have to use disp and num2str functions.

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Brian

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1 Answer

Answer by Walter Roberson on 4 Mar 2013

Hint:

[ 'E=mc^', num2str(2) ]

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Walter Roberson

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