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Having problems displaying the real and imaginary parts of a complex root

Asked by Suman Koirala on 12 Mar 2013

This is what I have. It works all fine in identifying the root but doesn't do anything with displaying the real and complex roots although I think I have it.

a=input('Enter a: ');
b=input('Enter b: ');
c=input('Enter c: ');
d=(b^2)- 4*a*c;
if d>0
    disp('This equation had two real roots');
    r1= (-b+sqrt(d))/(2*a)
    r2= (-b - sqrt(d))/(2*a)
elseif d==0
    disp('This equation has one real root');
    r1= (-b+sqrt(d))/(2*a)
else
    disp('This equation has two imaginary roots');
    r1= (-b+sqrt(d))/(2*a)
    r2= (-b - sqrt(d))/(2*a)
    real(r1)
    real(r2)
    y1=imag(r1)
    y2=imag(r2)
end

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Suman Koirala

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1 Answer

Answer by Youssef KHMOU on 12 Mar 2013
Accepted answer

hi, what is the problem exactly !

delete the part :

   real(r1);real(r2);
    y1=imag(r1);y2=imag(r2);

I think the code is fine :

 Enter a: 2
 Enter b: 2
 Enter c: 2
 This equation has two imaginary roots
 r1 =
-0.5000 + 0.8660i
 r2 =
-0.5000 - 0.8660i

1 Comment

Suman Koirala on 19 Mar 2013

THank you. It works fine.

Youssef  KHMOU

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