## Having problems displaying the real and imaginary parts of a complex root

on 12 Mar 2013

### Youssef Khmou (view profile)

This is what I have. It works all fine in identifying the root but doesn't do anything with displaying the real and complex roots although I think I have it.

```a=input('Enter a: ');
b=input('Enter b: ');
c=input('Enter c: ');
d=(b^2)- 4*a*c;
if d>0
disp('This equation had two real roots');
r1= (-b+sqrt(d))/(2*a)
r2= (-b - sqrt(d))/(2*a)
elseif d==0
disp('This equation has one real root');
r1= (-b+sqrt(d))/(2*a)
else
disp('This equation has two imaginary roots');
r1= (-b+sqrt(d))/(2*a)
r2= (-b - sqrt(d))/(2*a)
real(r1)
real(r2)
y1=imag(r1)
y2=imag(r2)
end
```

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### Youssef Khmou (view profile)

on 12 Mar 2013

hi, what is the problem exactly !

delete the part :

```   real(r1);real(r2);
y1=imag(r1);y2=imag(r2);```

I think the code is fine :

``` Enter a: 2
Enter b: 2
Enter c: 2
This equation has two imaginary roots```
` r1 =`
```-0.5000 + 0.8660i
```
` r2 =`
```-0.5000 - 0.8660i
```

Suman Koirala

### Suman Koirala (view profile)

on 19 Mar 2013

THank you. It works fine.

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