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Asked by Suman Koirala on 12 Mar 2013

This is what I have. It works all fine in identifying the root but doesn't do anything with displaying the real and complex roots although I think I have it.

a=input('Enter a: '); b=input('Enter b: '); c=input('Enter c: '); d=(b^2)- 4*a*c; if d>0 disp('This equation had two real roots'); r1= (-b+sqrt(d))/(2*a) r2= (-b - sqrt(d))/(2*a) elseif d==0 disp('This equation has one real root'); r1= (-b+sqrt(d))/(2*a) else disp('This equation has two imaginary roots'); r1= (-b+sqrt(d))/(2*a) r2= (-b - sqrt(d))/(2*a) real(r1) real(r2) y1=imag(r1) y2=imag(r2) end

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Answer by Youssef KHMOU on 12 Mar 2013

Accepted answer

hi, what is the problem exactly !

delete the part :

real(r1);real(r2); y1=imag(r1);y2=imag(r2);

I think the code is fine :

Enter a: 2 Enter b: 2 Enter c: 2 This equation has two imaginary roots

r1 =

-0.5000 + 0.8660i

r2 =

-0.5000 - 0.8660i

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